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Pertanyaan

Jika A^2x = 2 , maka A^5x - A^-5x / A^3x + A^-3x =

1 Jawaban

  • A^2x = 2
    A^x = √2

    → A^5x - A^-5x / A^3x + A^-3x

    = (√2)^5 - 1/(√2)^5 / (√2)^3 + 1/(√2)^3

    = 4√2 - 1/4√2 / 2√2 + 1/2√2

    = (16 . 2 - 1 / 4√2) / (4 . 2 + 1 / 2√2)

    = (32 - 1 / 4√2) / (8 + 1 / 2√2)

    = (31 / 4√2) / (9 / 2√2)

    = (31 / 4√2) x (2√2 / 9)

    = 31 / 9 x 2

    = 31 / 18

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