Matematika

Pertanyaan

tolong nomor 11dan 12 dan rumusnya
tolong nomor 11dan 12 dan rumusnya

2 Jawaban

  • 11)3a+20+2a=180
    5a+20=180
    5a=160
    a=160/5
    a=32
    Jadi besa
    12. 5x+3x+12=180
    8x+12=180
    8x=168
    x=21°
    Sudut pelurus = =3(21)+12=75°
  • 11. (3a+20) + 2a = 180°
     = 3a + 2a =180 - 20
     = 5a = 160
     a = 160/5
     a = 32
    ABD = (3×32+20)
    ABD = 116°
    12. 5x + (3x+12) = 180°
     = 5x + 3x = 180 - 12
     = 8x = 168
     x = 168/8
     x = 21
    SQR = (3×21+12)
    SQR = 75°