tolong dijawab ya makasih
Matematika
ShellyFanto
Pertanyaan
tolong dijawab ya makasih
1 Jawaban
-
1. Jawaban Robinn
1.
Lim cos5x - cos3x / 8x . sinx
x→0
Lim -2sin1/2(8x) sin1/2(2x)
x→0 .. / 8x . sinx
Lim -2 sin4x sinx
x→0 .. / 8x . sinx
Lim - sin4x . sinx
x→0 .. / 4x . sinx
Lim - (sin4x/4x) . (sinx/sinx)
x→0
= - (1) . 1
= -1
2.
Lim x (cos6x - 1) / sinx . tan²2x
x→0
Lim (cos6x - 1) / tan²2x
x→0
Lim (1 - 2sin²3x - 1)
x→0 .. / (2tanx/1 - tan²x)²
Lim -2sin²3x (1 - tan²x)²
x→0 .. / (2tanx)²
Lim -sin²3x (1 - tan²x)²
x→0 .. / tan²x
Lim - 3 (1 - tan²x)²
x→0
= -3 (1 - tan0)²
= -3 (1 - 0)²
= -3 (1)
= -3
.
3.
Lim x^3 + 3x² - 4x / √3 - √x + 3
x→0
Lim x (x² + 3x - 4)
x→0 .. / √3 - √x + 3
Lim x (x² + 3x - 4)(√3 + √x + 3)
x→0 .. / 3 - (x + 3)
Lim x (x² + 3x - 4)(√3 + √x + 3)
x→0 .. / 3 - x - 3
Lim x (x² + 3x - 4)(√3 + √x + 3)
x→0 .. / -x
Lim - (x² + 3x - 4)√3 + √x + 3)
x→0
= - (0 + 0 - 4)(√3 + √0 + 3)
= - (-4)(√3 + √3)
= 4 (2√3)
= 8√3
.
4.
Lim (√9x² - 4x - 3 - 3x - 2)
x→~
Lim (√9x² - 4x - 3 - (3x + 2)
x→~
Lim 9x² - 4x - 2 - (3x + 2)²
x→~ .. / (√9x² - 4x - 3 + (3x + 2)
Lim 9x² - 4x - 2 - (9x² + 12x + 4)
x→~ .. / (√9x² - 4x - 3 + (3x + 2)
Lim 9x² - 4x - 2 - 9x² - 12x - 4
x→~ .. / (√9x² - 4x - 3 + (3x + 2)
Lim -16x - 6
x→~ .. / (√x²(9 - 4/x - 3/x²) + x(3 + 2/x)
Lim x (-16 -6/x)
x→~ .. / x√9 - 4/x - 3/x² + x(3 + 2/x)
Lim -16 - 6/x
x→~ .. / √9 - 4/x - 3/x² + 3 + 2/x
= -16 - 0 / √9 - 0 - 0 + 3 + 0
= -16 / √9 + 3
= -16 / 3 + 3
= -16 / 6
= -8/3
.