1. x² - 8x + 12 = 2. 4a² + 17ab +4b² =

[tex]x^2-8x+12=(x-6)(x-2) \\ \\ ======================== \\ \\ 4a^2+17ab+4b^2= \frac{1}{4} (4a+16b)(4a+b) \\ \\ 4a^2+17ab+4b^2= \frac{1}{4} .4(a+4b)(4a+b) \\ \\ 4a^2+17ab+4b^2=(a+4b)(4a+b)[/tex]