fisika bab termodinamika, cuma 1 soal, butuh pembahasannya :)

V1 = 12 liter
T1 = 27+273 = 300K
Q = + 2kJ = +2000 J (menerima)
Isobarik
P = 2 × 10^5 Pa
T2 = 127+273 = 400K

(1) benar
V2 = (T2/T1). V1 = (400/300).12 L
V2 = 16 L

DeltaV = 16 - 12 = 4 L
Volume naik 4 L
Kalau (1) benar maka (3) benar

(2) benar
W = P . DeltaV
W = 2×10^5 . 4 liter
W = 2 × 10^5 . 4 × 10^-3
W = 8 × 10^2 joule
W = 0,8 kJ

(3) benar
Q = ∆U + W
∆U = Q - W
∆U = 2000 - 800
∆U = 1200 joule
∆U = 1,2 kJ

(4)
Massa jenis tidak berubah

Jawaban A