Matematika

Pertanyaan

Lim x-0 1-cos 8x per 4x2

1 Jawaban

  • LIMIT

    2sin^2 x = 1 - cos2x

    2sin^2 4x = 1-cos8x

    Lim (2sin^2 4x)/4x^2
    => 2× (4)^2 / 4
    => 2× 16/4
    => 2× 4
    => 8

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