tentukan fungsi dari soal dibawah: 1. f(x) = 2x + 1 2. f(x) = 3x + 1 (per) 5x -2 3. f(x)= 18x+3 makasiih :)

fungsi invers  , f(x) = y -->  f⁻¹(y)  = x

1)
f(x) = 2x + 1
f⁻¹ (2x+1) = x
2x+ 1 = y
2x = y-1
x= (y-1)/2
f⁻¹  (x)= (x -1) / 2

2)
f(x) = (3x+1)/(5x-2)
f⁻¹ { (3x+1)/(5x-2)} = x
(3x+1)/(5x-2) = y
y(5x-2) = 3x+1
5xy - 2y =  3x + 1
5xy - 3x = 2y +1
x(5y -3) = (2y +1)
x = (2y +1)/(5y -3)
f⁻¹ (x) = (2x+1)/(5x-3)

3. f(x)=  18x +3
f⁻¹(18x+3) =x
18x +3 = y
18x = y-3
x = (y-3)/18
f⁻¹(x) = (x-3)/18

Langsung aja y

Nomor 1
y = 2x + 1
2x = y-1
x = (y-1) / 2

f`¹(x) = (x - 1) / 2

Nomor 2
y = (3x + 1) / (5x-2)
y (5x-2) = 3x + 1
5xy - 2y = 3x + 1
5xy - 3x = 2y + 1
x (5y - 3) = 2y + 1
x = (2y + 1) / (5y - 3)

f`¹(x) = (2x + 1) / (5x - 3)

Nomor 3
y = 18x + 3
18x = y - 3
x = (y - 3) / 18

f`¹(x) = (x - 3) / 18

semoga berguna +_+