Diketahui persamaan kuadrat x²-8x+6 Tentukan: 1. 1/X1 + 1/X2 2. X1/X2 + X2/X1 3. 1/X1+1 + 1/X2+1 tolong ya gan...

X² - 8x + 6
>
x1 + x2 = 8
x1 * x2 = 6

1.) 1/x1 + 1/x2
= (x1+x2) / (x1*x2)
= 8 / 6
= 4 / 3

2.) x1/x2 + x2/x1
= (x1+x2)² - 2x1x2 / x1x2
= 64 - 12 / 6
= 52 / 6
= 26 / 3

3.) (1/x1 + 1) + (1/x2+1)
= (1 + x1 / x1) + (1 + x2 / x2)
= x2 + x1x2 + x1 + x1x2 / x1x2
= (x1+x2) + 2(x1x2) / x1x2
= ( 8 ) + 2 ( 6 ) / 6
= 8 + 12 / 6
= 20 / 6
= 10 / 3


koreksi bila salah