Matematika

Pertanyaan

tolong di jawab ya .........................
tolong di jawab ya .........................

1 Jawaban

  • Luas permukaan
    = 6s^2 +  (s[tex] \sqrt{2} [/tex] x t) + 2(sxt)
    = 6 x 50^2 cm^2 + (50[tex] \sqrt{2} [/tex] x 40) + 2(50x40) cm^2
    =  15.000 cm^2 + 2.000[tex] \sqrt{2} [/tex] cm^2 + 4.000 cm^2
    = 19.000 cm^2 + 2.000[tex] \sqrt{2} [/tex] cm^2
    = 2000(9,5 + [tex] \sqrt{2} [/tex] ) cm^2