Matematika

Pertanyaan

jika f(x)=2x^3-3x^2-4x-15,maka nilai f'(-5) adalah?
tolong di bantu ya

2 Jawaban

  • f(x) = 2x^3 - 3x^2 - 4x -15
    f'(x) = 6x^2 - 6x - 4
    f'(-5) = 6(-5)^2 - 6(-5) - 4
            = 6(25) + 30 - 4
            = 150 +30 - 4
            = 176

    maaf kalau salah yaa
     
  • f(x)=2x^3-3x^2-4x-15
    = 6x^2-6x-4
    f'(-5) = 6(-5)^2-6(-5)-4
    = 6.25+30-4
    =176

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