suatu prisma segiempat ABCD.EFGH luas permukaannya 62cm². Rusuk-rusuk alas 2cm dan 3cm. Hitung tinggi prisma

Lp = 2 (pl+lt+pt)
62 = 2 (3×2+2t+3t)
62:2 = 6 + 5t
31 - 6 = 5t
25:5 = t
| 5 = t |

Pembuktian :
62 = 2 (3×2+2×5+3×5)
62 = 2 (6 + 10 + 15)
62 = 2 × 31
• 62 = 62 •