tolong dong yang bisa sekarang

AB = 100

cos β = 1/2 √2  --> β = 45 --> tan  β = PQ/BP --> PQ/BP = 1
BP = PQ

sin α = 1/2 --> α = 30
tan α = PQ/ (100 +BP) = tan 30
PQ/(100+BP) =  1/√3
√3 (PQ) = 100 + BP  --> BP = PQ
√3 (PQ) =  100 + PQ
(√3- 1) (PQ) = 100
PQ = (100)/(√3-1)

PQ = 100 (√3 +1)/ (√3 - 1)(√3 +1)
PQ = 100(√3 +1) / (2)
PQ = 50 (√3 +1)
PQ = 50 + 50√3