Matematika

Pertanyaan

diketahui p(x)= 4x^3-2x^2+1 dan q(x)= x^4-nx^2+2. jika r(x)=p(x)-q(x) dan r(2)=39 makan n =...

2 Jawaban

  • r(x) = p(x) - q(x)
    = 4x³ - 2x² + 1 - (x^4 - nx² + 2)
    = 4x³ - 2x² - x^4 + nx² - 1
    untuk r(2) = 39
    4(2)³ - 2(2)² - 2^4 + n(2)² - 1 = 39
     32 - 8 - 16 + 4n - 1 = 39
    4n = 32
    n = 8
  • r(x) = p(x) - q(x)
    = [4x^3 - 2x^2 + 1] - [x^4 - nx^2 + 2]
    r(2) = [4×2^3-2×2^2+1] - [2^4-n×2^2+2] = 39
    = [4×8-2×4+1] - [16-n×4+2] = 39
    = [32-8+1] - [16-4n+2] = 39
    = [25] - [18-4n] = 39
    = 25 - 18 + 4n = 39
    = 7 + 4n = 39
    = 4n = 39 - 7
    4n = 32
    n = 32/4
    n = 8

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