Nilai minimum fungsi objektif(tujuan) f(x,y)=8x+y dengan kendala 3x+2y>_24, x>_2, y>_3

Ada 2 titik sudut :
1) 3x + 2y ≥ 24, x ≥ 2
3x + 2y = 24 => 3(2) + 2y = 24 => 2y = 18 => y = 9 => (2,9)

2) 3x + 2y ≥ 24, y ≥ 3
3x + 2y = 24 => 3x + 2(3) = 24 => 3x = 18 => x = 6 => (6,3)

Substitusi ke f(x,y) = 8x + y
1) (2,9) => 8(2) + 9 = 25
2) (6,3) => 8(6) + 3 = 51
Jadi nilai minimumnya = 25