Kimia

Pertanyaan

Ph larutan garam (nh4)2so40,2 m.jika diketahui (kbnh3=4x10-5)

1 Jawaban

  • (NH4)2SO4

    [H+] = √Kw / Kb . n . M
    [H+] = √10^-14 /4 x 10^-5 . 2 . 2 x 10^-1
    [H+] = √10^-9 . 10^-1 x 4 / 4
    [H+] = √10^-10
    [H+] = 10^-5

    pH = -log[H+]
    pH = -log10^-5
    pH = 5

Pertanyaan Lainnya