cara penyelesaian bilangan oksidasi Cr didalam Cr2O7
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Pertanyaan
cara penyelesaian bilangan oksidasi Cr didalam Cr2O7
2 Jawaban
-
1. Jawaban IkhsanHakiki
Cr2O7 =2Cr + 7O = 0
= 2Cr + 7(-2)= 0 -
2. Jawaban RahmatDarmaraga
Cr2O7 = 0
2 Cr + 7 O = 0
2Cr + 7(-2) = 0
2Cr - 14 = 0
2Cr = + 14
Cr = 14/2
Cr = + 7