Matematika

Pertanyaan

F(x)=(6x-3)^3(2x-1)
F¹(x)

2 Jawaban

  • u = (6x-3)³

    u' = 3(6x-3)².6

    = 18 (6x-3)²



    v = (2x-1)

    v' = 2


    f'(x) = u'v + v'u

    = 18 (6x-3)² (2x-1) + 2 (6x-3)³



  • F'(x) = 6×3(6x-3)^2 (2x-1) + (6x-3)^3 (2)
    F'(x)= 18(6x-3)^2(2x-1) + 2(6x-3)^3

    atau

    F'(x) = 2(6x-3)^2[9(2x-1) + (6x-3)]
    F'(x) = 2(6x-3)^2(18x-9+6x-3)
    F'(x) = 2(6x-3)^2(24x - 12)

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