Ini soalnya ttg perhitungan ph hidrolisis garam 1. Dik larutan NaCl 0.02 m Jika Ka 2.10pangkat-10 tentukan ph nya 2. Dik NH4Cl 0.01m jika Kb NH3 2.10pangkat-5 t

1.
[OH-] = √Kw / Ka . M
[OH-] = √10^-14 / 2 x 10^-10 (2 x 10^-2)
[OH-] = √10^-4 x 10^-2
[OH-] = √10^-6,
[OH-] = 10^-3

pOH = -log[OH-]
pOH = -log 10^-3
pOH = 3

pH = 14 - 3
pH = 11

2.
[H+] = √Kw / Kb . M
[H+] = √10^-14 / 2 . 10^-5 . 1 x 10^-2
[H+] = √10^-9 / 2 (10^-2)
[H+] = √10^-11 x 0,5
[H+] = √10^-12 x 5
[H+] = √5 x 10^-6

pH = -log[H+]
pH = -log√5 x 10^-6
pH = 6 - log√5

3.
[H+] = √Kw . Ka / Kb
[H+] = √10^-14 . 4 x 10^-10 / 2 x 10^-5
[H+] = √10^-19 x 2
[H+] = √10^-18 x 0,2
[H+] = √0,2 x 10^-9

pH = -log [H+]
pH = -log√0,2 x 10^-9
pH = 9 - log√0,2