Resonansi pertama terjadi pada panjang kolom 16 cm. Apabila cepat rambat bunyi di udara 192 m/s, hitunglah : a. Frekuensi garpu tala b. Panjang kolom udara pad

L 1 = 16 cm
v = 192 m/s
a. Frekuensi = ?
b. L 2 dan L 3 = ?
Penyelesaian:
L 1 = λ/4
16 = λ/4
λ = (16)(4)
λ = 64 cm = 0,64 m

a.
v = λf
192 = (0,64)f
f = 192/0,64
f = 300 Hz

b.
L 2 = (2n -1) λ/4
L 2 = (2.2 -1) λ/4
L 2 = 3/4 λ
L 2 = (3/4)(64)
L 2 = 48 cm

L 3 = (2n -1) λ/4
L 3 = (2.3 -1) λ/4
L 3 = (5/4) λ
L 3 = (5/4)(64)
L 3 = 80 cm