jika diketahui f(x-3) = (x-6) / (x+3) , maka f infers (1/2) =

f(x-3) = (x-6) / (x+3)
f((x-3)+3) = (x+3-6) / (x+3+3)
f(x-3+3) = (x-3) / (x+6)
f(x) = (x-3) / (x+6)
untuk mencari invers, kita misalkan f(x) = y
y = (x-3) / (x+6)
y (x+6) = (x-3)
xy + 6y = x - 3
xy = x - 3 - 6y
xy - x = - 3 - 6y
x (y-1) = -3-6y
x = (-3-6y) / (y-1)

maka, f invers (x) = (-3-6x) / (x-1)
f invers (½) = (-3-6(½) / (½-1)
f invers (½) = (-3-3) / (-½)
f invers (½) = -6 / -½
f invers (½) = -6 . -2
f invers (½) = 12

semoga mambantu