Persen massa metanol dalam Campuran adalah 92%. Jika 100 gram campuran tersebut dibakar sempurna, maka H2o yang dihasilkan adalah .. (Diketahui Ar C 12, H 1, O

m CH3OH = kadar × m camp = 92% × 100 gr = 92 gram

Mr CH3OH = Ar C + 4 Ar H + Ar O
Mr CH3OH = 12 + 4(1) + 16
Mr CH3OH = 32

n CH3OH = m / Mr = 92 gram / 32 = 2,875 mol

Reaksi :
2 CH3OH + 5 O2 => 2 CO2 + 4 H2O

n H2O = (koef H2O / koef CH3OH) × n CH3OH
n H2O = 4/2 × 2,875 mol = 5,75 mol

Mr H2O = 2 Ar H + Ar O = 2(1) + 16 = 18

m H2O = n × Mr = 5,75 mol × 18 = 103,5 gram

Jawaban : E