Mohon Bantuanya Kakak-Kakak
Matematika
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Pertanyaan
Mohon Bantuanya Kakak-Kakak
1 Jawaban
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1. Jawaban Lovinki
1. Karena AD : BD = 2 : 1, maka AD : AB = 2 : 3
Maka BC = [tex] \frac{3}{2} [/tex] × 6 = 9 cm
2. Karena CD : CA = 3 : 4, maka CE : CB = 3 : 4
CB = [tex] \frac{4}{3} [/tex] × 12 = 16
EB = CB - CE
EB = 16 - 12 = 4 cm
3. 10 - 2 = 8
DA = 8 cm, DE = 5cm
[tex]\frac{5}{8} [/tex] × 8 = 5 cm,
2 cm + 5 cm = 7 cm
EF = 7 cm
4. 13 - 3 = 10
DP : DA = 2 : 10
[tex] \frac{2}{10} [/tex] × 10 = 2
3 cm + 2 cm = 5 cm
PQ = 5 cm
6. 6x + 3 x = 90
9x = 90, x = 10°
∠AOB = 6x = 60°
7. 3x + 80 + 2x = 180°
5x = 100, x = 20°
∠COD = 2x = 40°
no 8 9 burek, benar2 gak kelihatan
Maaf kalo ada yg salah, soalnya gambarnya kurang jelas.